The power required is negligible.
The main thing is to make sure the phototransistor that you fit over the autofocus or PRINT led is well shielded from sunlight.
Basically, a resistor from a 4.5 to 6V supply is connected to the base of a general-purpose NPN transistor .. thus turning it on.
The collector of that transistor connects to the supply via a resistor and the collector also connects to the USB +ve connection.
So, normally the USB voltage is near zero.
The phototransistor connects from the other transistor base to ground.
When the led lights, the phototransistor conducts and pulls the other transistor base low .. hopefully low enough to turn it off.
The USB voltage rises to near the supply voltage and triggers the camera.
A convenient, small, light-weight source for the voltage is a tiny torch as sold by Frans :-
http://chdk.setepontos.com/index.php/topic,3631.msg33855.html#msg33855+6V is OK on the USB connector, it is a logic signal, not a voltage that has to adhere to the USB specification.
This circuit can be made and tested in minutes.
The phototransistor must be securely mounted.